*DECK SSCAL SUBROUTINE SSCAL (N, SA, SX, INCX) C***BEGIN PROLOGUE SSCAL C***PURPOSE Multiply a vector by a constant. C***LIBRARY SLATEC (BLAS) C***CATEGORY D1A6 C***TYPE SINGLE PRECISION (SSCAL-S, DSCAL-D, CSCAL-C) C***KEYWORDS BLAS, LINEAR ALGEBRA, SCALE, VECTOR C***AUTHOR Lawson, C. L., (JPL) C Hanson, R. J., (SNLA) C Kincaid, D. R., (U. of Texas) C Krogh, F. T., (JPL) C***DESCRIPTION C C B L A S Subprogram C Description of Parameters C C --Input-- C N number of elements in input vector(s) C SA single precision scale factor C SX single precision vector with N elements C INCX storage spacing between elements of SX C C --Output-- C SX single precision result (unchanged if N .LE. 0) C C Replace single precision SX by single precision SA*SX. C For I = 0 to N-1, replace SX(IX+I*INCX) with SA * SX(IX+I*INCX), C where IX = 1 if INCX .GE. 0, else IX = 1+(1-N)*INCX. C C***REFERENCES C. L. Lawson, R. J. Hanson, D. R. Kincaid and F. T. C Krogh, Basic linear algebra subprograms for Fortran C usage, Algorithm No. 539, Transactions on Mathematical C Software 5, 3 (September 1979), pp. 308-323. C***ROUTINES CALLED (NONE) C***REVISION HISTORY (YYMMDD) C 791001 DATE WRITTEN C 890831 Modified array declarations. (WRB) C 890831 REVISION DATE from Version 3.2 C 891214 Prologue converted to Version 4.0 format. (BAB) C 900821 Modified to correct problem with a negative increment. C (WRB) C 920501 Reformatted the REFERENCES section. (WRB) C***END PROLOGUE SSCAL REAL SA, SX(*) INTEGER I, INCX, IX, M, MP1, N C***FIRST EXECUTABLE STATEMENT SSCAL IF (N .LE. 0) RETURN IF (INCX .EQ. 1) GOTO 20 C C Code for increment not equal to 1. C IX = 1 IF (INCX .LT. 0) IX = (-N+1)*INCX + 1 DO 10 I = 1,N SX(IX) = SA*SX(IX) IX = IX + INCX 10 CONTINUE RETURN C C Code for increment equal to 1. C C Clean-up loop so remaining vector length is a multiple of 5. C 20 M = MOD(N,5) IF (M .EQ. 0) GOTO 40 DO 30 I = 1,M SX(I) = SA*SX(I) 30 CONTINUE IF (N .LT. 5) RETURN 40 MP1 = M + 1 DO 50 I = MP1,N,5 SX(I) = SA*SX(I) SX(I+1) = SA*SX(I+1) SX(I+2) = SA*SX(I+2) SX(I+3) = SA*SX(I+3) SX(I+4) = SA*SX(I+4) 50 CONTINUE RETURN END