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Replace amos with slatec
427 lines
13 KiB
Fortran
427 lines
13 KiB
Fortran
*DECK RC3JJ
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SUBROUTINE RC3JJ (L2, L3, M2, M3, L1MIN, L1MAX, THRCOF, NDIM, IER)
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C***BEGIN PROLOGUE RC3JJ
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C***PURPOSE Evaluate the 3j symbol f(L1) = ( L1 L2 L3)
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C (-M2-M3 M2 M3)
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C for all allowed values of L1, the other parameters
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C being held fixed.
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C***LIBRARY SLATEC
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C***CATEGORY C19
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C***TYPE SINGLE PRECISION (RC3JJ-S, DRC3JJ-D)
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C***KEYWORDS 3J COEFFICIENTS, 3J SYMBOLS, CLEBSCH-GORDAN COEFFICIENTS,
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C RACAH COEFFICIENTS, VECTOR ADDITION COEFFICIENTS,
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C WIGNER COEFFICIENTS
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C***AUTHOR Gordon, R. G., Harvard University
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C Schulten, K., Max Planck Institute
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C***DESCRIPTION
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C
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C *Usage:
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C
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C REAL L2, L3, M2, M3, L1MIN, L1MAX, THRCOF(NDIM)
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C INTEGER NDIM, IER
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C
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C CALL RC3JJ (L2, L3, M2, M3, L1MIN, L1MAX, THRCOF, NDIM, IER)
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C
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C *Arguments:
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C
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C L2 :IN Parameter in 3j symbol.
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C
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C L3 :IN Parameter in 3j symbol.
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C
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C M2 :IN Parameter in 3j symbol.
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C
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C M3 :IN Parameter in 3j symbol.
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C
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C L1MIN :OUT Smallest allowable L1 in 3j symbol.
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C
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C L1MAX :OUT Largest allowable L1 in 3j symbol.
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C
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C THRCOF :OUT Set of 3j coefficients generated by evaluating the
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C 3j symbol for all allowed values of L1. THRCOF(I)
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C will contain f(L1MIN+I-1), I=1,2,...,L1MAX+L1MIN+1.
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C
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C NDIM :IN Declared length of THRCOF in calling program.
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C
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C IER :OUT Error flag.
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C IER=0 No errors.
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C IER=1 Either L2.LT.ABS(M2) or L3.LT.ABS(M3).
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C IER=2 Either L2+ABS(M2) or L3+ABS(M3) non-integer.
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C IER=3 L1MAX-L1MIN not an integer.
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C IER=4 L1MAX less than L1MIN.
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C IER=5 NDIM less than L1MAX-L1MIN+1.
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C
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C *Description:
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C
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C Although conventionally the parameters of the vector addition
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C coefficients satisfy certain restrictions, such as being integers
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C or integers plus 1/2, the restrictions imposed on input to this
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C subroutine are somewhat weaker. See, for example, Section 27.9 of
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C Abramowitz and Stegun or Appendix C of Volume II of A. Messiah.
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C The restrictions imposed by this subroutine are
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C 1. L2 .GE. ABS(M2) and L3 .GE. ABS(M3);
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C 2. L2+ABS(M2) and L3+ABS(M3) must be integers;
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C 3. L1MAX-L1MIN must be a non-negative integer, where
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C L1MAX=L2+L3 and L1MIN=MAX(ABS(L2-L3),ABS(M2+M3)).
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C If the conventional restrictions are satisfied, then these
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C restrictions are met.
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C
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C The user should be cautious in using input parameters that do
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C not satisfy the conventional restrictions. For example, the
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C the subroutine produces values of
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C f(L1) = ( L1 2.5 5.8)
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C (-0.3 1.5 -1.2)
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C for L1=3.3,4.3,...,8.3 but none of the symmetry properties of the 3j
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C symbol, set forth on page 1056 of Messiah, is satisfied.
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C
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C The subroutine generates f(L1MIN), f(L1MIN+1), ..., f(L1MAX)
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C where L1MIN and L1MAX are defined above. The sequence f(L1) is
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C generated by a three-term recurrence algorithm with scaling to
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C control overflow. Both backward and forward recurrence are used to
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C maintain numerical stability. The two recurrence sequences are
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C matched at an interior point and are normalized from the unitary
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C property of 3j coefficients and Wigner's phase convention.
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C
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C The algorithm is suited to applications in which large quantum
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C numbers arise, such as in molecular dynamics.
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C
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C***REFERENCES 1. Abramowitz, M., and Stegun, I. A., Eds., Handbook
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C of Mathematical Functions with Formulas, Graphs
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C and Mathematical Tables, NBS Applied Mathematics
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C Series 55, June 1964 and subsequent printings.
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C 2. Messiah, Albert., Quantum Mechanics, Volume II,
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C North-Holland Publishing Company, 1963.
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C 3. Schulten, Klaus and Gordon, Roy G., Exact recursive
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C evaluation of 3j and 6j coefficients for quantum-
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C mechanical coupling of angular momenta, J Math
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C Phys, v 16, no. 10, October 1975, pp. 1961-1970.
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C 4. Schulten, Klaus and Gordon, Roy G., Semiclassical
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C approximations to 3j and 6j coefficients for
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C quantum-mechanical coupling of angular momenta,
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C J Math Phys, v 16, no. 10, October 1975,
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C pp. 1971-1988.
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C 5. Schulten, Klaus and Gordon, Roy G., Recursive
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C evaluation of 3j and 6j coefficients, Computer
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C Phys Comm, v 11, 1976, pp. 269-278.
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C***ROUTINES CALLED R1MACH, XERMSG
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C***REVISION HISTORY (YYMMDD)
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C 750101 DATE WRITTEN
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C 880515 SLATEC prologue added by G. C. Nielson, NBS; parameters
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C HUGE and TINY revised to depend on R1MACH.
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C 891229 Prologue description rewritten; other prologue sections
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C revised; LMATCH (location of match point for recurrences)
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C removed from argument list; argument IER changed to serve
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C only as an error flag (previously, in cases without error,
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C it returned the number of scalings); number of error codes
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C increased to provide more precise error information;
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C program comments revised; SLATEC error handler calls
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C introduced to enable printing of error messages to meet
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C SLATEC standards. These changes were done by D. W. Lozier,
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C M. A. McClain and J. M. Smith of the National Institute
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C of Standards and Technology, formerly NBS.
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C 910415 Mixed type expressions eliminated; variable C1 initialized;
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C description of THRCOF expanded. These changes were done by
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C D. W. Lozier.
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C***END PROLOGUE RC3JJ
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C
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INTEGER NDIM, IER
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REAL L2, L3, M2, M3, L1MIN, L1MAX, THRCOF(NDIM)
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C
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INTEGER I, INDEX, LSTEP, N, NFIN, NFINP1, NFINP2, NFINP3, NLIM,
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+ NSTEP2
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REAL A1, A1S, A2, A2S, C1, C1OLD, C2, CNORM, R1MACH,
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+ DENOM, DV, EPS, HUGE, L1, M1, NEWFAC, OLDFAC,
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+ ONE, RATIO, SIGN1, SIGN2, SRHUGE, SRTINY, SUM1,
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+ SUM2, SUMBAC, SUMFOR, SUMUNI, THREE, THRESH,
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+ TINY, TWO, X, X1, X2, X3, Y, Y1, Y2, Y3, ZERO
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C
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DATA ZERO,EPS,ONE,TWO,THREE /0.0,0.01,1.0,2.0,3.0/
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C
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C***FIRST EXECUTABLE STATEMENT RC3JJ
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IER=0
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C HUGE is the square root of one twentieth of the largest floating
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C point number, approximately.
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HUGE = SQRT(R1MACH(2)/20.0)
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SRHUGE = SQRT(HUGE)
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TINY = 1.0/HUGE
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SRTINY = 1.0/SRHUGE
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C
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C LMATCH = ZERO
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M1 = - M2 - M3
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C
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C Check error conditions 1 and 2.
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IF((L2-ABS(M2)+EPS.LT.ZERO).OR.
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+ (L3-ABS(M3)+EPS.LT.ZERO))THEN
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IER=1
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CALL XERMSG('SLATEC','RC3JJ','L2-ABS(M2) or L3-ABS(M3) '//
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+ 'less than zero.',IER,1)
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RETURN
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ELSEIF((MOD(L2+ABS(M2)+EPS,ONE).GE.EPS+EPS).OR.
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+ (MOD(L3+ABS(M3)+EPS,ONE).GE.EPS+EPS))THEN
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IER=2
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CALL XERMSG('SLATEC','RC3JJ','L2+ABS(M2) or L3+ABS(M3) '//
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+ 'not integer.',IER,1)
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RETURN
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ENDIF
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C
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C
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C
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C Limits for L1
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C
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L1MIN = MAX(ABS(L2-L3),ABS(M1))
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L1MAX = L2 + L3
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C
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C Check error condition 3.
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IF(MOD(L1MAX-L1MIN+EPS,ONE).GE.EPS+EPS)THEN
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IER=3
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CALL XERMSG('SLATEC','RC3JJ','L1MAX-L1MIN not integer.',IER,1)
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RETURN
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ENDIF
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IF(L1MIN.LT.L1MAX-EPS) GO TO 20
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IF(L1MIN.LT.L1MAX+EPS) GO TO 10
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C
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C Check error condition 4.
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IER=4
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CALL XERMSG('SLATEC','RC3JJ','L1MIN greater than L1MAX.',IER,1)
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RETURN
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C
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C This is reached in case that L1 can take only one value,
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C i.e. L1MIN = L1MAX
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C
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10 CONTINUE
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C LSCALE = 0
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THRCOF(1) = (-ONE) ** INT(ABS(L2+M2-L3+M3)+EPS) /
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1 SQRT(L1MIN + L2 + L3 + ONE)
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RETURN
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C
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C This is reached in case that L1 takes more than one value,
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C i.e. L1MIN < L1MAX.
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C
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20 CONTINUE
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C LSCALE = 0
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NFIN = INT(L1MAX-L1MIN+ONE+EPS)
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IF(NDIM-NFIN) 21, 23, 23
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C
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C Check error condition 5.
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21 IER = 5
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CALL XERMSG('SLATEC','RC3JJ','Dimension of result array for 3j '//
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+ 'coefficients too small.',IER,1)
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RETURN
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C
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C
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C Starting forward recursion from L1MIN taking NSTEP1 steps
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C
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23 L1 = L1MIN
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NEWFAC = 0.0
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C1 = 0.0
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THRCOF(1) = SRTINY
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SUM1 = (L1+L1+ONE) * TINY
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C
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C
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LSTEP = 1
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30 LSTEP = LSTEP + 1
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L1 = L1 + ONE
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C
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C
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OLDFAC = NEWFAC
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A1 = (L1+L2+L3+ONE) * (L1-L2+L3) * (L1+L2-L3) * (-L1+L2+L3+ONE)
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A2 = (L1+M1) * (L1-M1)
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NEWFAC = SQRT(A1*A2)
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IF(L1.LT.ONE+EPS) GO TO 40
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C
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C
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DV = - L2*(L2+ONE) * M1 + L3*(L3+ONE) * M1 + L1*(L1-ONE) * (M3-M2)
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DENOM = (L1-ONE) * NEWFAC
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C
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IF(LSTEP-2) 32, 32, 31
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C
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31 C1OLD = ABS(C1)
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32 C1 = - (L1+L1-ONE) * DV / DENOM
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GO TO 50
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C
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C If L1 = 1, (L1-1) has to be factored out of DV, hence
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C
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40 C1 = - (L1+L1-ONE) * L1 * (M3-M2) / NEWFAC
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C
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50 IF(LSTEP.GT.2) GO TO 60
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C
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C
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C If L1 = L1MIN + 1, the third term in the recursion equation vanishes,
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C hence
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X = SRTINY * C1
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THRCOF(2) = X
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SUM1 = SUM1 + TINY * (L1+L1+ONE) * C1*C1
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IF(LSTEP.EQ.NFIN) GO TO 220
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GO TO 30
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C
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C
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60 C2 = - L1 * OLDFAC / DENOM
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C
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C Recursion to the next 3j coefficient X
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C
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X = C1 * THRCOF(LSTEP-1) + C2 * THRCOF(LSTEP-2)
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THRCOF(LSTEP) = X
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SUMFOR = SUM1
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SUM1 = SUM1 + (L1+L1+ONE) * X*X
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IF(LSTEP.EQ.NFIN) GO TO 100
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C
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C See if last unnormalized 3j coefficient exceeds SRHUGE
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C
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IF(ABS(X).LT.SRHUGE) GO TO 80
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C
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C This is reached if last 3j coefficient larger than SRHUGE,
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C so that the recursion series THRCOF(1), ... , THRCOF(LSTEP)
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C has to be rescaled to prevent overflow
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C
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C LSCALE = LSCALE + 1
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DO 70 I=1,LSTEP
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IF(ABS(THRCOF(I)).LT.SRTINY) THRCOF(I) = ZERO
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70 THRCOF(I) = THRCOF(I) / SRHUGE
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SUM1 = SUM1 / HUGE
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SUMFOR = SUMFOR / HUGE
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X = X / SRHUGE
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C
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C As long as ABS(C1) is decreasing, the recursion proceeds towards
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C increasing 3j values and, hence, is numerically stable. Once
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C an increase of ABS(C1) is detected, the recursion direction is
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C reversed.
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C
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80 IF(C1OLD-ABS(C1)) 100, 100, 30
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C
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C
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C Keep three 3j coefficients around LMATCH for comparison with
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C backward recursion.
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C
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100 CONTINUE
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C LMATCH = L1 - 1
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X1 = X
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X2 = THRCOF(LSTEP-1)
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X3 = THRCOF(LSTEP-2)
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NSTEP2 = NFIN - LSTEP + 3
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C
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C
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C
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C
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C Starting backward recursion from L1MAX taking NSTEP2 steps, so
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C that forward and backward recursion overlap at three points
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C L1 = LMATCH+1, LMATCH, LMATCH-1.
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C
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NFINP1 = NFIN + 1
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NFINP2 = NFIN + 2
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NFINP3 = NFIN + 3
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L1 = L1MAX
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THRCOF(NFIN) = SRTINY
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SUM2 = TINY * (L1+L1+ONE)
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C
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L1 = L1 + TWO
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LSTEP = 1
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110 LSTEP = LSTEP + 1
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L1 = L1 - ONE
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C
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OLDFAC = NEWFAC
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A1S = (L1+L2+L3)*(L1-L2+L3-ONE)*(L1+L2-L3-ONE)*(-L1+L2+L3+TWO)
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A2S = (L1+M1-ONE) * (L1-M1-ONE)
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NEWFAC = SQRT(A1S*A2S)
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C
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DV = - L2*(L2+ONE) * M1 + L3*(L3+ONE) * M1 + L1*(L1-ONE) * (M3-M2)
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C
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DENOM = L1 * NEWFAC
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C1 = - (L1+L1-ONE) * DV / DENOM
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IF(LSTEP.GT.2) GO TO 120
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C
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C If L1 = L1MAX + 1, the third term in the recursion formula vanishes
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C
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Y = SRTINY * C1
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THRCOF(NFIN-1) = Y
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SUMBAC = SUM2
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SUM2 = SUM2 + TINY * (L1+L1-THREE) * C1*C1
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C
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GO TO 110
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C
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C
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120 C2 = - (L1 - ONE) * OLDFAC / DENOM
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C
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C Recursion to the next 3j coefficient Y
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C
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Y = C1 * THRCOF(NFINP2-LSTEP) + C2 * THRCOF(NFINP3-LSTEP)
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C
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IF(LSTEP.EQ.NSTEP2) GO TO 200
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C
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THRCOF(NFINP1-LSTEP) = Y
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SUMBAC = SUM2
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SUM2 = SUM2 + (L1+L1-THREE) * Y*Y
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C
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C See if last unnormalized 3j coefficient exceeds SRHUGE
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C
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IF(ABS(Y).LT.SRHUGE) GO TO 110
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C
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C This is reached if last 3j coefficient larger than SRHUGE,
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C so that the recursion series THRCOF(NFIN), ... ,THRCOF(NFIN-LSTEP+1)
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C has to be rescaled to prevent overflow
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C
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C LSCALE = LSCALE + 1
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DO 130 I=1,LSTEP
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INDEX = NFIN - I + 1
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IF(ABS(THRCOF(INDEX)).LT.SRTINY) THRCOF(INDEX) = ZERO
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130 THRCOF(INDEX) = THRCOF(INDEX) / SRHUGE
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SUM2 = SUM2 / HUGE
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SUMBAC = SUMBAC / HUGE
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C
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C
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GO TO 110
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C
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C
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C The forward recursion 3j coefficients X1, X2, X3 are to be matched
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C with the corresponding backward recursion values Y1, Y2, Y3.
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C
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200 Y3 = Y
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Y2 = THRCOF(NFINP2-LSTEP)
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Y1 = THRCOF(NFINP3-LSTEP)
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C
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C
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C Determine now RATIO such that YI = RATIO * XI (I=1,2,3) holds
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C with minimal error.
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C
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RATIO = ( X1*Y1 + X2*Y2 + X3*Y3 ) / ( X1*X1 + X2*X2 + X3*X3 )
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NLIM = NFIN - NSTEP2 + 1
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C
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IF(ABS(RATIO).LT.ONE) GO TO 211
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C
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DO 210 N=1,NLIM
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210 THRCOF(N) = RATIO * THRCOF(N)
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SUMUNI = RATIO * RATIO * SUMFOR + SUMBAC
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GO TO 230
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C
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211 NLIM = NLIM + 1
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RATIO = ONE / RATIO
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DO 212 N=NLIM,NFIN
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212 THRCOF(N) = RATIO * THRCOF(N)
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SUMUNI = SUMFOR + RATIO*RATIO*SUMBAC
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GO TO 230
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C
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220 SUMUNI = SUM1
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C
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C
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C Normalize 3j coefficients
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C
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230 CNORM = ONE / SQRT(SUMUNI)
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C
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C Sign convention for last 3j coefficient determines overall phase
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C
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SIGN1 = SIGN(ONE,THRCOF(NFIN))
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SIGN2 = (-ONE) ** INT(ABS(L2+M2-L3+M3)+EPS)
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IF(SIGN1*SIGN2) 235,235,236
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235 CNORM = - CNORM
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C
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236 IF(ABS(CNORM).LT.ONE) GO TO 250
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C
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DO 240 N=1,NFIN
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240 THRCOF(N) = CNORM * THRCOF(N)
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RETURN
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C
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250 THRESH = TINY / ABS(CNORM)
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DO 251 N=1,NFIN
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IF(ABS(THRCOF(N)).LT.THRESH) THRCOF(N) = ZERO
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251 THRCOF(N) = CNORM * THRCOF(N)
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C
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RETURN
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END
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