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c977aa998f
Replace amos with slatec
278 lines
9.9 KiB
Fortran
278 lines
9.9 KiB
Fortran
*DECK QZVEC
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SUBROUTINE QZVEC (NM, N, A, B, ALFR, ALFI, BETA, Z)
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C***BEGIN PROLOGUE QZVEC
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C***PURPOSE The optional fourth step of the QZ algorithm for
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C generalized eigenproblems. Accepts a matrix in
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C quasi-triangular form and another in upper triangular
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C and computes the eigenvectors of the triangular problem
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C and transforms them back to the original coordinates
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C Usually preceded by QZHES, QZIT, and QZVAL.
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C***LIBRARY SLATEC (EISPACK)
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C***CATEGORY D4C3
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C***TYPE SINGLE PRECISION (QZVEC-S)
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C***KEYWORDS EIGENVALUES, EIGENVECTORS, EISPACK
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C***AUTHOR Smith, B. T., et al.
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C***DESCRIPTION
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C
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C This subroutine is the optional fourth step of the QZ algorithm
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C for solving generalized matrix eigenvalue problems,
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C SIAM J. NUMER. ANAL. 10, 241-256(1973) by MOLER and STEWART.
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C
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C This subroutine accepts a pair of REAL matrices, one of them in
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C quasi-triangular form (in which each 2-by-2 block corresponds to
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C a pair of complex eigenvalues) and the other in upper triangular
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C form. It computes the eigenvectors of the triangular problem and
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C transforms the results back to the original coordinate system.
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C It is usually preceded by QZHES, QZIT, and QZVAL.
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C
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C On Input
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C
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C NM must be set to the row dimension of the two-dimensional
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C array parameters, A, B, and Z, as declared in the calling
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C program dimension statement. NM is an INTEGER variable.
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C
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C N is the order of the matrices A and B. N is an INTEGER
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C variable. N must be less than or equal to NM.
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C
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C A contains a real upper quasi-triangular matrix. A is a two-
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C dimensional REAL array, dimensioned A(NM,N).
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C
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C B contains a real upper triangular matrix. In addition,
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C location B(N,1) contains the tolerance quantity (EPSB)
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C computed and saved in QZIT. B is a two-dimensional REAL
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C array, dimensioned B(NM,N).
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C
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C ALFR, ALFI, and BETA are one-dimensional REAL arrays with
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C components whose ratios ((ALFR+I*ALFI)/BETA) are the
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C generalized eigenvalues. They are usually obtained from
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C QZVAL. They are dimensioned ALFR(N), ALFI(N), and BETA(N).
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C
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C Z contains the transformation matrix produced in the reductions
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C by QZHES, QZIT, and QZVAL, if performed. If the
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C eigenvectors of the triangular problem are desired, Z must
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C contain the identity matrix. Z is a two-dimensional REAL
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C array, dimensioned Z(NM,N).
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C
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C On Output
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C
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C A is unaltered. Its subdiagonal elements provide information
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C about the storage of the complex eigenvectors.
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C
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C B has been destroyed.
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C
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C ALFR, ALFI, and BETA are unaltered.
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C
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C Z contains the real and imaginary parts of the eigenvectors.
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C If ALFI(J) .EQ. 0.0, the J-th eigenvalue is real and
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C the J-th column of Z contains its eigenvector.
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C If ALFI(J) .NE. 0.0, the J-th eigenvalue is complex.
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C If ALFI(J) .GT. 0.0, the eigenvalue is the first of
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C a complex pair and the J-th and (J+1)-th columns
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C of Z contain its eigenvector.
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C If ALFI(J) .LT. 0.0, the eigenvalue is the second of
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C a complex pair and the (J-1)-th and J-th columns
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C of Z contain the conjugate of its eigenvector.
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C Each eigenvector is normalized so that the modulus
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C of its largest component is 1.0 .
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C
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C Questions and comments should be directed to B. S. Garbow,
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C APPLIED MATHEMATICS DIVISION, ARGONNE NATIONAL LABORATORY
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C ------------------------------------------------------------------
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C
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C***REFERENCES B. T. Smith, J. M. Boyle, J. J. Dongarra, B. S. Garbow,
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C Y. Ikebe, V. C. Klema and C. B. Moler, Matrix Eigen-
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C system Routines - EISPACK Guide, Springer-Verlag,
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C 1976.
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C***ROUTINES CALLED (NONE)
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C***REVISION HISTORY (YYMMDD)
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C 760101 DATE WRITTEN
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C 890831 Modified array declarations. (WRB)
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C 890831 REVISION DATE from Version 3.2
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C 891214 Prologue converted to Version 4.0 format. (BAB)
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C 920501 Reformatted the REFERENCES section. (WRB)
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C***END PROLOGUE QZVEC
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C
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INTEGER I,J,K,M,N,EN,II,JJ,NA,NM,NN,ISW,ENM2
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REAL A(NM,*),B(NM,*),ALFR(*),ALFI(*),BETA(*),Z(NM,*)
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REAL D,Q,R,S,T,W,X,Y,DI,DR,RA,RR,SA,TI,TR,T1,T2
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REAL W1,X1,ZZ,Z1,ALFM,ALMI,ALMR,BETM,EPSB
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C
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C***FIRST EXECUTABLE STATEMENT QZVEC
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EPSB = B(N,1)
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ISW = 1
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C .......... FOR EN=N STEP -1 UNTIL 1 DO -- ..........
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DO 800 NN = 1, N
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EN = N + 1 - NN
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NA = EN - 1
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IF (ISW .EQ. 2) GO TO 795
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IF (ALFI(EN) .NE. 0.0E0) GO TO 710
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C .......... REAL VECTOR ..........
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M = EN
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B(EN,EN) = 1.0E0
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IF (NA .EQ. 0) GO TO 800
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ALFM = ALFR(M)
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BETM = BETA(M)
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C .......... FOR I=EN-1 STEP -1 UNTIL 1 DO -- ..........
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DO 700 II = 1, NA
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I = EN - II
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W = BETM * A(I,I) - ALFM * B(I,I)
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R = 0.0E0
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C
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DO 610 J = M, EN
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610 R = R + (BETM * A(I,J) - ALFM * B(I,J)) * B(J,EN)
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C
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IF (I .EQ. 1 .OR. ISW .EQ. 2) GO TO 630
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IF (BETM * A(I,I-1) .EQ. 0.0E0) GO TO 630
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ZZ = W
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S = R
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GO TO 690
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630 M = I
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IF (ISW .EQ. 2) GO TO 640
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C .......... REAL 1-BY-1 BLOCK ..........
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T = W
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IF (W .EQ. 0.0E0) T = EPSB
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B(I,EN) = -R / T
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GO TO 700
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C .......... REAL 2-BY-2 BLOCK ..........
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640 X = BETM * A(I,I+1) - ALFM * B(I,I+1)
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Y = BETM * A(I+1,I)
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Q = W * ZZ - X * Y
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T = (X * S - ZZ * R) / Q
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B(I,EN) = T
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IF (ABS(X) .LE. ABS(ZZ)) GO TO 650
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B(I+1,EN) = (-R - W * T) / X
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GO TO 690
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650 B(I+1,EN) = (-S - Y * T) / ZZ
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690 ISW = 3 - ISW
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700 CONTINUE
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C .......... END REAL VECTOR ..........
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GO TO 800
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C .......... COMPLEX VECTOR ..........
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710 M = NA
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ALMR = ALFR(M)
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ALMI = ALFI(M)
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BETM = BETA(M)
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C .......... LAST VECTOR COMPONENT CHOSEN IMAGINARY SO THAT
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C EIGENVECTOR MATRIX IS TRIANGULAR ..........
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Y = BETM * A(EN,NA)
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B(NA,NA) = -ALMI * B(EN,EN) / Y
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B(NA,EN) = (ALMR * B(EN,EN) - BETM * A(EN,EN)) / Y
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B(EN,NA) = 0.0E0
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B(EN,EN) = 1.0E0
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ENM2 = NA - 1
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IF (ENM2 .EQ. 0) GO TO 795
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C .......... FOR I=EN-2 STEP -1 UNTIL 1 DO -- ..........
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DO 790 II = 1, ENM2
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I = NA - II
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W = BETM * A(I,I) - ALMR * B(I,I)
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W1 = -ALMI * B(I,I)
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RA = 0.0E0
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SA = 0.0E0
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C
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DO 760 J = M, EN
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X = BETM * A(I,J) - ALMR * B(I,J)
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X1 = -ALMI * B(I,J)
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RA = RA + X * B(J,NA) - X1 * B(J,EN)
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SA = SA + X * B(J,EN) + X1 * B(J,NA)
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760 CONTINUE
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C
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IF (I .EQ. 1 .OR. ISW .EQ. 2) GO TO 770
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IF (BETM * A(I,I-1) .EQ. 0.0E0) GO TO 770
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ZZ = W
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Z1 = W1
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R = RA
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S = SA
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ISW = 2
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GO TO 790
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770 M = I
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IF (ISW .EQ. 2) GO TO 780
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C .......... COMPLEX 1-BY-1 BLOCK ..........
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TR = -RA
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TI = -SA
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773 DR = W
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DI = W1
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C .......... COMPLEX DIVIDE (T1,T2) = (TR,TI) / (DR,DI) ..........
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775 IF (ABS(DI) .GT. ABS(DR)) GO TO 777
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RR = DI / DR
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D = DR + DI * RR
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T1 = (TR + TI * RR) / D
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T2 = (TI - TR * RR) / D
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GO TO (787,782), ISW
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777 RR = DR / DI
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D = DR * RR + DI
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T1 = (TR * RR + TI) / D
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T2 = (TI * RR - TR) / D
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GO TO (787,782), ISW
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C .......... COMPLEX 2-BY-2 BLOCK ..........
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780 X = BETM * A(I,I+1) - ALMR * B(I,I+1)
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X1 = -ALMI * B(I,I+1)
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Y = BETM * A(I+1,I)
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TR = Y * RA - W * R + W1 * S
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TI = Y * SA - W * S - W1 * R
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DR = W * ZZ - W1 * Z1 - X * Y
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DI = W * Z1 + W1 * ZZ - X1 * Y
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IF (DR .EQ. 0.0E0 .AND. DI .EQ. 0.0E0) DR = EPSB
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GO TO 775
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782 B(I+1,NA) = T1
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B(I+1,EN) = T2
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ISW = 1
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IF (ABS(Y) .GT. ABS(W) + ABS(W1)) GO TO 785
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TR = -RA - X * B(I+1,NA) + X1 * B(I+1,EN)
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TI = -SA - X * B(I+1,EN) - X1 * B(I+1,NA)
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GO TO 773
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785 T1 = (-R - ZZ * B(I+1,NA) + Z1 * B(I+1,EN)) / Y
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T2 = (-S - ZZ * B(I+1,EN) - Z1 * B(I+1,NA)) / Y
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787 B(I,NA) = T1
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B(I,EN) = T2
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790 CONTINUE
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C .......... END COMPLEX VECTOR ..........
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795 ISW = 3 - ISW
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800 CONTINUE
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C .......... END BACK SUBSTITUTION.
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C TRANSFORM TO ORIGINAL COORDINATE SYSTEM.
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C FOR J=N STEP -1 UNTIL 1 DO -- ..........
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DO 880 JJ = 1, N
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J = N + 1 - JJ
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C
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DO 880 I = 1, N
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ZZ = 0.0E0
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C
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DO 860 K = 1, J
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860 ZZ = ZZ + Z(I,K) * B(K,J)
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C
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Z(I,J) = ZZ
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880 CONTINUE
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C .......... NORMALIZE SO THAT MODULUS OF LARGEST
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C COMPONENT OF EACH VECTOR IS 1.
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C (ISW IS 1 INITIALLY FROM BEFORE) ..........
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DO 950 J = 1, N
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D = 0.0E0
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IF (ISW .EQ. 2) GO TO 920
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IF (ALFI(J) .NE. 0.0E0) GO TO 945
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C
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DO 890 I = 1, N
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IF (ABS(Z(I,J)) .GT. D) D = ABS(Z(I,J))
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890 CONTINUE
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C
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DO 900 I = 1, N
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900 Z(I,J) = Z(I,J) / D
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C
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GO TO 950
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C
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920 DO 930 I = 1, N
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R = ABS(Z(I,J-1)) + ABS(Z(I,J))
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IF (R .NE. 0.0E0) R = R * SQRT((Z(I,J-1)/R)**2
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1 +(Z(I,J)/R)**2)
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IF (R .GT. D) D = R
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930 CONTINUE
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C
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DO 940 I = 1, N
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Z(I,J-1) = Z(I,J-1) / D
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Z(I,J) = Z(I,J) / D
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940 CONTINUE
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C
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945 ISW = 3 - ISW
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950 CONTINUE
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C
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RETURN
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END
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