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128 lines
4.6 KiB
Fortran
128 lines
4.6 KiB
Fortran
*DECK RADF5
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SUBROUTINE RADF5 (IDO, L1, CC, CH, WA1, WA2, WA3, WA4)
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C***BEGIN PROLOGUE RADF5
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C***SUBSIDIARY
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C***PURPOSE Calculate the fast Fourier transform of subvectors of
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C length five.
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C***LIBRARY SLATEC (FFTPACK)
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C***TYPE SINGLE PRECISION (RADF5-S)
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C***AUTHOR Swarztrauber, P. N., (NCAR)
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C***ROUTINES CALLED (NONE)
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C***REVISION HISTORY (YYMMDD)
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C 790601 DATE WRITTEN
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C 830401 Modified to use SLATEC library source file format.
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C 860115 Modified by Ron Boisvert to adhere to Fortran 77 by
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C (a) changing dummy array size declarations (1) to (*),
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C (b) changing definition of variables PI, TI11, TI12,
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C TR11, TR12 by using FORTRAN intrinsic functions ATAN
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C and SIN instead of DATA statements.
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C 881128 Modified by Dick Valent to meet prologue standards.
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C 890831 Modified array declarations. (WRB)
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C 891214 Prologue converted to Version 4.0 format. (BAB)
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C 900402 Added TYPE section. (WRB)
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C***END PROLOGUE RADF5
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DIMENSION CC(IDO,L1,5), CH(IDO,5,*), WA1(*), WA2(*), WA3(*),
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+ WA4(*)
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C***FIRST EXECUTABLE STATEMENT RADF5
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PI = 4.*ATAN(1.)
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TR11 = SIN(.1*PI)
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TI11 = SIN(.4*PI)
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TR12 = -SIN(.3*PI)
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TI12 = SIN(.2*PI)
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DO 101 K=1,L1
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CR2 = CC(1,K,5)+CC(1,K,2)
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CI5 = CC(1,K,5)-CC(1,K,2)
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CR3 = CC(1,K,4)+CC(1,K,3)
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CI4 = CC(1,K,4)-CC(1,K,3)
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CH(1,1,K) = CC(1,K,1)+CR2+CR3
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CH(IDO,2,K) = CC(1,K,1)+TR11*CR2+TR12*CR3
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CH(1,3,K) = TI11*CI5+TI12*CI4
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CH(IDO,4,K) = CC(1,K,1)+TR12*CR2+TR11*CR3
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CH(1,5,K) = TI12*CI5-TI11*CI4
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101 CONTINUE
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IF (IDO .EQ. 1) RETURN
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IDP2 = IDO+2
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IF((IDO-1)/2.LT.L1) GO TO 104
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DO 103 K=1,L1
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CDIR$ IVDEP
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DO 102 I=3,IDO,2
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IC = IDP2-I
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DR2 = WA1(I-2)*CC(I-1,K,2)+WA1(I-1)*CC(I,K,2)
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DI2 = WA1(I-2)*CC(I,K,2)-WA1(I-1)*CC(I-1,K,2)
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DR3 = WA2(I-2)*CC(I-1,K,3)+WA2(I-1)*CC(I,K,3)
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DI3 = WA2(I-2)*CC(I,K,3)-WA2(I-1)*CC(I-1,K,3)
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DR4 = WA3(I-2)*CC(I-1,K,4)+WA3(I-1)*CC(I,K,4)
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DI4 = WA3(I-2)*CC(I,K,4)-WA3(I-1)*CC(I-1,K,4)
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DR5 = WA4(I-2)*CC(I-1,K,5)+WA4(I-1)*CC(I,K,5)
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DI5 = WA4(I-2)*CC(I,K,5)-WA4(I-1)*CC(I-1,K,5)
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CR2 = DR2+DR5
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CI5 = DR5-DR2
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CR5 = DI2-DI5
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CI2 = DI2+DI5
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CR3 = DR3+DR4
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CI4 = DR4-DR3
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CR4 = DI3-DI4
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CI3 = DI3+DI4
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CH(I-1,1,K) = CC(I-1,K,1)+CR2+CR3
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CH(I,1,K) = CC(I,K,1)+CI2+CI3
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TR2 = CC(I-1,K,1)+TR11*CR2+TR12*CR3
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TI2 = CC(I,K,1)+TR11*CI2+TR12*CI3
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TR3 = CC(I-1,K,1)+TR12*CR2+TR11*CR3
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TI3 = CC(I,K,1)+TR12*CI2+TR11*CI3
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TR5 = TI11*CR5+TI12*CR4
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TI5 = TI11*CI5+TI12*CI4
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TR4 = TI12*CR5-TI11*CR4
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TI4 = TI12*CI5-TI11*CI4
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CH(I-1,3,K) = TR2+TR5
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CH(IC-1,2,K) = TR2-TR5
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CH(I,3,K) = TI2+TI5
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CH(IC,2,K) = TI5-TI2
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CH(I-1,5,K) = TR3+TR4
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CH(IC-1,4,K) = TR3-TR4
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CH(I,5,K) = TI3+TI4
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CH(IC,4,K) = TI4-TI3
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102 CONTINUE
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103 CONTINUE
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RETURN
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104 DO 106 I=3,IDO,2
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IC = IDP2-I
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CDIR$ IVDEP
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DO 105 K=1,L1
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DR2 = WA1(I-2)*CC(I-1,K,2)+WA1(I-1)*CC(I,K,2)
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DI2 = WA1(I-2)*CC(I,K,2)-WA1(I-1)*CC(I-1,K,2)
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DR3 = WA2(I-2)*CC(I-1,K,3)+WA2(I-1)*CC(I,K,3)
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DI3 = WA2(I-2)*CC(I,K,3)-WA2(I-1)*CC(I-1,K,3)
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DR4 = WA3(I-2)*CC(I-1,K,4)+WA3(I-1)*CC(I,K,4)
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DI4 = WA3(I-2)*CC(I,K,4)-WA3(I-1)*CC(I-1,K,4)
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DR5 = WA4(I-2)*CC(I-1,K,5)+WA4(I-1)*CC(I,K,5)
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DI5 = WA4(I-2)*CC(I,K,5)-WA4(I-1)*CC(I-1,K,5)
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CR2 = DR2+DR5
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CI5 = DR5-DR2
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CR5 = DI2-DI5
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CI2 = DI2+DI5
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CR3 = DR3+DR4
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CI4 = DR4-DR3
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CR4 = DI3-DI4
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CI3 = DI3+DI4
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CH(I-1,1,K) = CC(I-1,K,1)+CR2+CR3
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CH(I,1,K) = CC(I,K,1)+CI2+CI3
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TR2 = CC(I-1,K,1)+TR11*CR2+TR12*CR3
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TI2 = CC(I,K,1)+TR11*CI2+TR12*CI3
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TR3 = CC(I-1,K,1)+TR12*CR2+TR11*CR3
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TI3 = CC(I,K,1)+TR12*CI2+TR11*CI3
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TR5 = TI11*CR5+TI12*CR4
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TI5 = TI11*CI5+TI12*CI4
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TR4 = TI12*CR5-TI11*CR4
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TI4 = TI12*CI5-TI11*CI4
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CH(I-1,3,K) = TR2+TR5
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CH(IC-1,2,K) = TR2-TR5
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CH(I,3,K) = TI2+TI5
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CH(IC,2,K) = TI5-TI2
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CH(I-1,5,K) = TR3+TR4
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CH(IC-1,4,K) = TR3-TR4
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CH(I,5,K) = TI3+TI4
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CH(IC,4,K) = TI4-TI3
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105 CONTINUE
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106 CONTINUE
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RETURN
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END
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