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c977aa998f
Replace amos with slatec
100 lines
3 KiB
Fortran
100 lines
3 KiB
Fortran
*DECK SPPFA
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SUBROUTINE SPPFA (AP, N, INFO)
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C***BEGIN PROLOGUE SPPFA
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C***PURPOSE Factor a real symmetric positive definite matrix stored in
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C packed form.
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C***LIBRARY SLATEC (LINPACK)
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C***CATEGORY D2B1B
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C***TYPE SINGLE PRECISION (SPPFA-S, DPPFA-D, CPPFA-C)
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C***KEYWORDS LINEAR ALGEBRA, LINPACK, MATRIX FACTORIZATION, PACKED,
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C POSITIVE DEFINITE
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C***AUTHOR Moler, C. B., (U. of New Mexico)
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C***DESCRIPTION
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C
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C SPPFA factors a real symmetric positive definite matrix
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C stored in packed form.
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C
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C SPPFA is usually called by SPPCO, but it can be called
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C directly with a saving in time if RCOND is not needed.
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C (Time for SPPCO) = (1 + 18/N)*(Time for SPPFA) .
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C
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C On Entry
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C
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C AP REAL (N*(N+1)/2)
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C the packed form of a symmetric matrix A . The
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C columns of the upper triangle are stored sequentially
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C in a one-dimensional array of length N*(N+1)/2 .
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C See comments below for details.
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C
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C N INTEGER
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C the order of the matrix A .
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C
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C On Return
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C
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C AP an upper triangular matrix R , stored in packed
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C form, so that A = TRANS(R)*R .
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C
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C INFO INTEGER
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C = 0 for normal return.
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C = K if the leading minor of order K is not
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C positive definite.
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C
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C
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C Packed Storage
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C
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C The following program segment will pack the upper
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C triangle of a symmetric matrix.
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C
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C K = 0
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C DO 20 J = 1, N
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C DO 10 I = 1, J
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C K = K + 1
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C AP(K) = A(I,J)
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C 10 CONTINUE
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C 20 CONTINUE
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C
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C***REFERENCES J. J. Dongarra, J. R. Bunch, C. B. Moler, and G. W.
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C Stewart, LINPACK Users' Guide, SIAM, 1979.
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C***ROUTINES CALLED SDOT
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C***REVISION HISTORY (YYMMDD)
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C 780814 DATE WRITTEN
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C 890831 Modified array declarations. (WRB)
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C 890831 REVISION DATE from Version 3.2
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C 891214 Prologue converted to Version 4.0 format. (BAB)
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C 900326 Removed duplicate information from DESCRIPTION section.
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C (WRB)
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C 920501 Reformatted the REFERENCES section. (WRB)
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C***END PROLOGUE SPPFA
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INTEGER N,INFO
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REAL AP(*)
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C
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REAL SDOT,T
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REAL S
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INTEGER J,JJ,JM1,K,KJ,KK
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C***FIRST EXECUTABLE STATEMENT SPPFA
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JJ = 0
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DO 30 J = 1, N
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INFO = J
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S = 0.0E0
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JM1 = J - 1
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KJ = JJ
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KK = 0
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IF (JM1 .LT. 1) GO TO 20
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DO 10 K = 1, JM1
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KJ = KJ + 1
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T = AP(KJ) - SDOT(K-1,AP(KK+1),1,AP(JJ+1),1)
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KK = KK + K
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T = T/AP(KK)
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AP(KJ) = T
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S = S + T*T
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10 CONTINUE
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20 CONTINUE
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JJ = JJ + J
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S = AP(JJ) - S
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IF (S .LE. 0.0E0) GO TO 40
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AP(JJ) = SQRT(S)
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30 CONTINUE
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INFO = 0
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40 CONTINUE
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RETURN
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END
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