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71 lines
1.5 KiB
Scheme
71 lines
1.5 KiB
Scheme
;;; Temporary testing, delete this once it works
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;(define (call2 fn x y)
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; (write
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; (fn x y)))
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;
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;(define (call fn a)
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; (fn a))
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;
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;(call write 'hello)
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;
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;;; Demonstrate sending an interpreted function to compiled code
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;;; I think in order for this to work, the compiled code would have to
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;;; detect an interpreted proc, and use eval to execute it
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;
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;;; TODO: to debug this, may try placing printfs in runtime's apply
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;(eval '(call2 (lambda (x y) (+ y x)) 2 3))
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;;(eval '(call (lambda (x) (+ 1 x)) (display (+ 1 1))))
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;;(eval '(call write 1))
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;;(eval '(call mywrite 1))
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;
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;(eval '(define (a x) x))
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;(eval '(a 1))
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;(eval '(a 1))
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;(eval '(begin (define (a z) z) (a 1) (a 1)))
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(write
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(with-exception-handler
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(lambda (con)
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(cond
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((string? con)
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(display con))
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(else
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(display "a warning has been issued")))
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42)
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(lambda ()
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(+ (raise-continuable "should be a number") 23)
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)))
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;prints: should be a number
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;=> 65
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(write
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(call/cc
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(lambda (k)
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(with-exception-handler
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(lambda (x)
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(display "condition: ")
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(write x)
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;(newline)
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(k 'exception))
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(lambda ()
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(+ 1 (raise 'an-error)))))))
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(with-exception-handler
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(lambda (x)
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(display "something went wrong\n"))
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(lambda ()
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(+ 1 (raise 'an-error))))
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(define test '(a b))
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(set-car! test '(1 2 3))
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(write test)
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(raise 'done)
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(define (loop n)
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(cond
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((= n 10000)
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(write test)
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(loop 0))
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(else
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(loop (+ n 1)))))
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(loop 0)
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